![]() Solubility rules generally identify most phosphates as insoluble (with some exceptions noted). Please include state symbols in the answer.Ĭu 3PO 4 is insoluble. Problem #29: Write the net ionic equation for the following reaction:ģCuCl + (NH 4) 3PO 4 -> 3NH 4Cl + Cu 3PO 4 What you have to be able to do is (1) predict the correct products and (2) identify them as soluble, ionic substances (that will then dissociate 100% in solution). Since nothing is left, we call it NR.Ĭomment: when the question writer intends NR to be the answer, you will often see the reaction asked with products not present: That means that each substance ionizes 100% to give this total ionic equation:īa 2+(aq) + 2Cl -(aq) + Mg 2+(aq) + 2NO 3 -(aq) -> Mg 2+(aq) + 2Cl -(aq) + Ba 2+(aq) + 2NO 3 -(aq)Įverything is identical on each side of the arrow, so everything is eliminated for being a spectator ion. Notice that all four substances are ionic and soluble. This is an example of no reaction (commonly signified as NR). Problem #28: Write the net ionic equation for the following reaction:īaCl 2(aq) + Mg(NO 3) 2(aq) -> MgCl 2(aq) + Ba(NO 3) 2(aq) On the left-hand side, two hydrogen ions and two hydroxide ions reacted to form two water molecules.Ĥ) A second round of removing spectators gives the final answer: Notice that there are hydrogen ions and hydroxide ions on the left-hand side of the arrow. However, in this example, the sulfuric acid will react completely, so we treat it as fully dissociated.Ģ) Here is the net ionic equation (after removal of all spectator ions):ĢAl 3+(aq) + 8OH -(aq) + 2H +(aq) -> 2Al(OH) 3(s) + 2H 2O(ℓ) ![]() When H 2SO 4 is dissolved in water, its dissociation is complex and will not be discussed here. Note that the sulfuric acid is treated as fully dissociated. This problem is illustrative of the main problem students face in doing net ionic problems: you have to know a large amount of seemingly random bits of information (like the fact that iron(III) chloride forms a complex). It turns out there is an iron(III) chloride complex, formula = FeCl 4. Solution: If you tried to do double replacement, you'd get the same products as reactants and so you would write this reaction as NR (no reaction). Iron(III) chloride + hydrochloric acid -> Problem #26: Complete the reaction & write the net ionic equation: ChemTeam: Complete Molecular, Complete Ionic and Net Ionic: Twenty-Five Problems Complete Molecular, Complete Ionic and Net Ionic: Twenty-Five Problems Ten Problems Fifteen Problems Net ionic equation tutorial All NR Equations & Reaction Types menu
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